7. Lagrange multipliers. - Lars-Erik Persson
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In the figure below we have illustrated an extreme value problem with constraints. The point A is the largest value of the function z=f(x,y) while the point B is the largest value of the function under the constraintg(x,y)=0. Theorem: (Lagrange multipliers) Let f and g be differntiable functions, where f’x(x0,y0) and f’y(x0,y0) not both are zero. If the function f(x,y) has an extreme value in the point (x0,y0) under the constraint g(x,y)=0, then there is a constant such … Continued
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